Задание 110. Выполните действия. A. 1) 20⋅(-2)+10(-5) = 2)-20-(-2)+10(-5) = 3) 20-2-10(-5) = 4)-20-2-10.5 = 5) 20⋅(-2)+10.5 = 6)-20-(-2)-10.5 = 7)-20-2-10-(-5) = 8) 20-2-10.5 = 9)-20-(-2)-10-(-5) = 10) 20-(-2)-10.5 = Б. 1) 10(-4) + 15 (-2)+25-(-2) = 2)-10-(-4)+15-(-2) - 25. (-2) = 3)-10-4-15-2-25-2 = 4) 10-4-15-(-2)+25-(-2) = 5)-10-4+15(-2)-25-(-2) = 6)-10-(-4)-15-(-2)-25-2 = 7) 10(-4)-15-(-2) +25.2 = 8) 10-4-15-2-25-(-2) = 9) (-10)-(-4)+15+(-2)-25-2= 10)-10-4-15-2-25-(-2) =

Решение:

А.

1. 20 \(\cdot\) (-2) + 10 \(\cdot\) (-5) = -40 - 50 = -90
2. -20 - (-2) + 10 \(\cdot\) (-5) = -20 + 2 - 50 = -68
3. 20 - 2 - 10 \(\cdot\) (-5) = 18 + 50 = 68
4. -20 - 2 - 10 \(\cdot\) 5 = -22 - 50 = -72
5. 20 \(\cdot\) (-2) + 10 \(\cdot\) 5 = -40 + 50 = 10
6. -20 - (-2) - 10 \(\cdot\) 5 = -20 + 2 - 50 = -68
7. -20 - 2 - 10 \(\cdot\) (-5) = -22 + 50 = 28
8. 20 - 2 - 10 \(\cdot\) 5 = 18 - 50 = -32
9. -20 - (-2) - 10 \(\cdot\) (-5) = -20 + 2 + 50 = 32
10. 20 - (-2) - 10 \(\cdot\) 5 = 20 + 2 - 50 = -28

Б.

1. 10 \(\cdot\) (-4) + 15 \(\cdot\) (-2) + 25 \(\cdot\) (-2) = -40 - 30 - 50 = -120
2. -10 - (-4) + 15 \(\cdot\) (-2) - 25 \(\cdot\) (-2) = -10 + 4 - 30 + 50 = 14
3. -10 - 4 - 15 - 2 - 25 - 2 = -58
4. 10 - 4 - 15 - (-2) + 25 \(\cdot\) (-2) = 10 - 4 - 15 + 2 - 50 = -57
5. -10 - 4 + 15 \(\cdot\) (-2) - 25 \(\cdot\) (-2) = -10 - 4 - 30 + 50 = 6
6. -10 - (-4) - 15 - (-2) - 25 \(\cdot\) 2 = -10 + 4 - 15 + 2 - 50 = -69
7. 10 \(\cdot\) (-4) - 15 \(\cdot\) (-2) + 25 \(\cdot\) 2 = -40 + 30 + 50 = 40
8. 10 - 4 - 15 - 2 - 25 \(\cdot\) (-2) = 10 - 4 - 15 - 2 + 50 = 39
9. (-10) - (-4) + 15 + (-2) - 25 - 2 = -10 + 4 + 15 - 2 - 25 - 2 = -20
10. -10 - 4 - 15 - 2 - 25 \(\cdot\) (-2) = -10 - 4 - 15 - 2 + 50 = 19

Ответ: А. 1) -90, 2) -68, 3) 68, 4) -72, 5) 10, 6) -68, 7) 28, 8) -32, 9) 32, 10) -28; Б. 1) -120, 2) 14, 3) -58, 4) -57, 5) 6, 6) -69, 7) 40, 8) 39, 9) -20, 10) 19

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