Задание: ∛(−1/27) + √0,09

\(\sqrt[3]{-\frac{1}{27}}=-\frac{1}{3}\), \(\sqrt{0.09}=0.3=\frac{3}{10}\).

\(-\frac{1}{3}+\frac{3}{10}=-\frac{10}{30}+\frac{9}{30}=-\frac{1}{30}\).

Ответ: \(-\frac{1}{30}\).