Вопрос:

Задание 1. Найдите значение выражения: 1) \(\frac{3}{4}\cdot\frac{6}{5}\); 2) \(\frac{21}{5}\cdot\frac{3}{7}\); 7) \(\frac{12}{5} : \frac{15}{2}\); 8) \(\frac{6}{5} : \frac{4}{11}\); 13) \(\frac{1}{4}-\frac{3}{25}\); 14) \(\frac{1}{5}-\frac{27}{50}\); 19) \(\frac{14}{25}+\frac{3}{2}\); 20) \(\frac{9}{4}+\frac{8}{5}\).

Ответ:

  1. \(\frac{3}{4}\cdot\frac{6}{5}=\frac{18}{20}=\frac{9}{10}\).
  2. \(\frac{21}{5}\cdot\frac{3}{7}=\frac{63}{35}=\frac{9}{5}=1\frac{4}{5}\).
  3. \(\frac{12}{5}:\frac{15}{2}=\frac{12}{5}\cdot\frac{2}{15}=\frac{24}{75}=\frac{8}{25}\).
  4. \(\frac{6}{5}:\frac{4}{11}=\frac{6}{5}\cdot\frac{11}{4}=\frac{66}{20}=\frac{33}{10}=3\frac{3}{10}\).
  5. \(\frac{1}{4}-\frac{3}{25}=\frac{25}{100}-\frac{12}{100}=\frac{13}{100}\).
  6. \(\frac{1}{5}-\frac{27}{50}=\frac{10}{50}-\frac{27}{50}=-\frac{17}{50}\).
  7. \(\frac{14}{25}+\frac{3}{2}=\frac{28}{50}+\frac{75}{50}=\frac{103}{50}=2\frac{3}{50}\).
  8. \(\frac{9}{4}+\frac{8}{5}=\frac{45}{20}+\frac{32}{20}=\frac{77}{20}=3\frac{17}{20}\).

Ответ: 1) \(\frac{9}{10}\); 2) \(1\frac{4}{5}\); 7) \(\frac{8}{25}\); 8) \(3\frac{3}{10}\); 13) \(\frac{13}{100}\); 14) \(-\frac{17}{50}\); 19) \(2\frac{3}{50}\); 20) \(3\frac{17}{20}\).

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