Задание 1. Вычислите: а) 8 7/8 − 3 1/5; б) 7 7/12 − 1 5/6 + 3 1/2.

1. \(8\frac{7}{8}-3\frac{1}{5}=\frac{71}{8}-\frac{16}{5}=\frac{355-128}{40}=\frac{227}{40}=5\frac{27}{40}.\)

2. \(7\frac{7}{12}-1\frac{5}{6}+3\frac{1}{2}=\frac{91}{12}-\frac{11}{6}+\frac{7}{2}=\frac{91-22+42}{12}=\frac{111}{12}=9\frac{1}{4}.\)

Ответ: а) \(5\frac{27}{40}\); б) \(9\frac{1}{4}\).