Задание 2. 1. (4 5/9 + 3 7/9) · 1/3 = 2. (6 2/7 · 7/4) · 4/3 = 3. (36/120 − 7/60) : (1/6 · 2/5) = 4. (1/9 · 3/2) · (4/9 · 9/2) =

1. \(\left(4\frac{5}{9}+3\frac{7}{9}\right)\cdot\frac{1}{3}=\left(7+\frac{12}{9}\right)\cdot\frac{1}{3}=\frac{25}{3}\cdot\frac{1}{3}=\frac{25}{9}\).
2. \(\left(6\frac{2}{7}\cdot\frac{7}{4}\right)\cdot\frac{4}{3}=\left(\frac{44}{7}\cdot\frac{7}{4}\right)\cdot\frac{4}{3}=11\cdot\frac{4}{3}=\frac{44}{3}\).
3. \(\left(\frac{36}{120}-\frac{7}{60}\right):\left(\frac{1}{6}\cdot\frac{2}{5}\right)=\left(\frac{3}{10}-\frac{7}{60}\right):\frac{1}{15}=\frac{11}{60}\cdot15=\frac{11}{4}\).
4. \(\left(\frac{1}{9}\cdot\frac{3}{2}\right)\cdot\left(\frac{4}{9}\cdot\frac{9}{2}\right)=\frac{1}{6}\cdot2=\frac{1}{3}\).

Ответ: 1) \(\frac{25}{9}\); 2) \(\frac{44}{3}\); 3) \(\frac{11}{4}\); 4) \(\frac{1}{3}\).