Задание 2. 1. (5 3/7 + 2 4/7) : 1/7 = 2. (8 4/10 − 5/6) · 6/5 · 2/9 = 3. (24/90 − 7/45) : 1 3/5 = 4. (1/6 · 3/4) · (4/6 · 6/4) =

1. \(5\frac{3}{7} + 2\frac{4}{7} = 7 + \frac{7}{7} = 8\).

\(8 : \frac{1}{7} = 8 \cdot 7 = 56\).

2. \(8\frac{4}{10} - \frac{5}{6} = \frac{42}{5} - \frac{5}{6} = \frac{227}{30}\).

\(\frac{227}{30} \cdot \frac{6}{5} \cdot \frac{2}{9} = \frac{454}{225}\).

3. \(\frac{24}{90} - \frac{7}{45} = \frac{12}{45} - \frac{7}{45} = \frac{1}{9}\).

\(\frac{1}{9} : 1\frac{3}{5} = \frac{1}{9} : \frac{8}{5} = \frac{1}{9} \cdot \frac{5}{8} = \frac{5}{72}\).

4. \(\left(\frac{1}{6} \cdot \frac{3}{4}\right) \cdot \left(\frac{4}{6} \cdot \frac{6}{4}\right) = \frac{1}{8} \cdot 1 = \frac{1}{8}\).

Ответ: 1) 56; 2) \(\frac{454}{225}\); 3) \(\frac{5}{72}\); 4) \(\frac{1}{8}\).