Ответ:

  1. \(\left(\frac{3}{4}+\frac{1}{2}\right)\cdot8-\frac{1}{4}=\left(\frac{3}{4}+\frac{2}{4}\right)\cdot8-\frac{1}{4}=\frac{5}{4}\cdot8-\frac{1}{4}=10-\frac{1}{4}=\frac{39}{4}=9\frac{3}{4}\).

  2. \(\left(\frac{5}{6}-\frac{1}{3}\right):\frac{1}{3}+\frac{2}{3}=\left(\frac{5}{6}-\frac{2}{6}\right):\frac{1}{3}+\frac{2}{3}=\frac{1}{2}\cdot3+\frac{2}{3}=\frac{3}{2}+\frac{2}{3}=\frac{13}{6}=2\frac{1}{6}\).

  3. \(\left(\frac{7}{8}-\frac{1}{4}\right)\cdot16+\frac{3}{4}=\left(\frac{7}{8}-\frac{2}{8}\right)\cdot16+\frac{3}{4}=\frac{5}{8}\cdot16+\frac{3}{4}=10+\frac{3}{4}=\frac{43}{4}=10\frac{3}{4}\).

  4. \(\left(\frac{2}{3}+\frac{1}{6}\right):\frac{1}{2}-\frac{1}{3}=\left(\frac{4}{6}+\frac{1}{6}\right):\frac{1}{2}-\frac{1}{3}=\frac{5}{6}\cdot2-\frac{1}{3}=\frac{5}{3}-\frac{1}{3}=\frac{4}{3}=1\frac{1}{3}\).

Ответ: 5) \(9\frac{3}{4}\); 6) \(2\frac{1}{6}\); 7) \(10\frac{3}{4}\); 8) \(1\frac{1}{3}\).