Ответ:

  1. \(\left(\frac{17}{10}-\frac{2}{20}\right)\cdot15=\left(\frac{34}{20}-\frac{2}{20}\right)\cdot15=\frac{8}{5}\cdot15=24\).
  2. На изображении знак и множитель после скобок читаются неуверенно. Если там \(\cdot11\), то \(\left(\frac{5}{22}-\frac{8}{11}\right)\cdot11=\left(\frac{5}{22}-\frac{16}{22}\right)\cdot11=-\frac{1}{2}\cdot11=-\frac{11}{2}\). Если там \(:1\), то \(\left(\frac{5}{22}-\frac{8}{11}\right):1=-\frac{1}{2}\).
  3. \(\left(\frac{5}{26}-\frac{3}{25}\right)\cdot\frac{13}{2}=\frac{47}{650}\cdot\frac{13}{2}=\frac{47}{100}\).
  4. \(\left(\frac{10}{13}+\frac{15}{4}\right):5=\frac{235}{52}:5=\frac{47}{52}\).
  5. \(\left(\frac{17}{26}+\frac{11}{13}\right)\cdot\frac{17}{6}=\frac{3}{2}\cdot\frac{17}{6}=\frac{17}{4}\).
  6. \(\left(\frac{11}{12}+\frac{11}{20}\right)\cdot\frac{15}{8}=\frac{22}{15}\cdot\frac{15}{8}=\frac{11}{4}\).
  7. \(\left(\frac{3}{4}-\frac{1}{6}\right)\cdot3=\frac{7}{12}\cdot3=\frac{7}{4}\).
  8. \(\left(\frac{2}{5}-\frac{13}{15}\right)\cdot6=-\frac{7}{15}\cdot6=-\frac{14}{5}\).
  9. \(\left(\frac{3}{8}-\frac{1}{20}\right)\cdot10=\frac{13}{40}\cdot10=\frac{13}{4}\).
  10. \(\left(\frac{2}{20}+\frac{7}{30}\right)\cdot15=\frac{1}{3}\cdot15=5\).
  11. \(\left(\frac{9}{10}-\frac{7}{15}\right)\cdot3=\frac{13}{30}\cdot3=\frac{13}{10}\).
  12. \(\left(\frac{1}{6}+\frac{4}{7}\right)\cdot9=\frac{31}{42}\cdot9=\frac{93}{14}\).