Задание №2. Вычислите обыкновенные дроби, а потом сократите: (9/14 − 2/7) + 9/35; (3/4 − 1/6) + 7/12; 7/15 + (8/9 − 5/6); (7/18 − 1/6) + 7/9; 12/170 + 13/17 − 2/34; 15/17 − (1/5 + 1/6).

1. \(\left(\frac{9}{14}-\frac{2}{7}\right)+\frac{9}{35}=\frac{5}{14}+\frac{9}{35}=\frac{25}{70}+\frac{18}{70}=\frac{43}{70}\).
2. \(\left(\frac{3}{4}-\frac{1}{6}\right)+\frac{7}{12}=\frac{7}{12}+\frac{7}{12}=\frac{14}{12}=\frac{7}{6}\).
3. \(\frac{7}{15}+\left(\frac{8}{9}-\frac{5}{6}\right)=\frac{7}{15}+\frac{1}{18}=\frac{42}{90}+\frac{5}{90}=\frac{47}{90}\).
4. \(\left(\frac{7}{18}-\frac{1}{6}\right)+\frac{7}{9}=\frac{4}{18}+\frac{14}{18}=1\).
5. \(\frac{12}{170}+\frac{13}{17}-\frac{2}{34}=\frac{6}{85}+\frac{65}{85}-\frac{5}{85}=\frac{66}{85}\).
6. \(\frac{15}{17}-\left(\frac{1}{5}+\frac{1}{6}\right)=\frac{15}{17}-\frac{11}{30}=\frac{450}{510}-\frac{187}{510}=\frac{263}{510}\).

Ответ: \(\frac{43}{70};\ \frac{7}{6};\ \frac{47}{90};\ 1;\ \frac{66}{85};\ \frac{263}{510}\).