Ответ:
\(\left(2\frac{3}{17}+\frac{1}{34}\right)\cdot17=\left(\frac{37}{17}+\frac{1}{34}\right)\cdot17=\frac{75}{34}\cdot17=\frac{75}{2}=37\frac{1}{2}\).
\(\left(1\frac{1}{4}-\frac{3}{19}\right)\cdot19=\left(\frac{5}{4}-\frac{3}{19}\right)\cdot19=\frac{83}{76}\cdot19=\frac{83}{4}=20\frac{3}{4}\).
\(4\frac{3}{8}:\left(\frac{3}{8}+1\frac{4}{13}\right)=\frac{35}{8}:\left(\frac{3}{8}+\frac{17}{13}\right)=\frac{35}{8}:\frac{175}{104}=\frac{35}{8}\cdot\frac{104}{175}=\frac{13}{5}=2\frac{3}{5}\).
\(5\frac{2}{5}:\left(3\frac{1}{4}-2\frac{4}{5}\right)=\frac{27}{5}:\left(\frac{13}{4}-\frac{14}{5}\right)=\frac{27}{5}:\frac{9}{20}=\frac{27}{5}\cdot\frac{20}{9}=12\).
Ответ: 1) \(37\frac{1}{2}\); 2) \(20\frac{3}{4}\); 3) \(2\frac{3}{5}\); 4) \(12\).
