Ответ:
4)
\(\frac{1}{10}+\frac{1}{5}=\frac{1}{10}+\frac{2}{10}=\frac{3}{10}\).
\(\frac{3}{15}-\frac{2}{4}=\frac{1}{5}-\frac{1}{2}=\frac{2}{10}-\frac{5}{10}=-\frac{3}{10}\).
Так как \(\frac{3}{10}>-\frac{3}{10}\), то \(\frac{1}{10}+\frac{1}{5}>\frac{3}{15}-\frac{2}{4}\).
5)
\(\frac{11}{12}\cdot\frac{21}{25}=\frac{77}{100}\).
\(\frac{2}{25}:\frac{2}{21}=\frac{2}{25}\cdot\frac{21}{2}=\frac{21}{25}=\frac{84}{100}\).
Так как \(\frac{77}{100}<\frac{84}{100}\), то \(\frac{11}{12}\cdot\frac{21}{25}<\frac{2}{25}:\frac{2}{21}\).
Ответ: 4) >; 5) <.
