Задание 34. Вычислите. А. 1) $\frac{11}{12}-\left(\frac{1}{3}+\frac{1}{4}\right)$; 2) $\frac{7}{24}+\left(\frac{1}{2}+\frac{1}{2}\right)$; 3) $\frac{7}{15}-\left(\frac{2}{3}-\frac{1}{5}\right)$; 4) $\frac{13}{21}+\left(\frac{2}{3}-\frac{3}{7}\right)$; 5) $\frac{2}{9}+\left(\frac{5}{18}+\frac{5}{12}\right)$; 6) $\frac{5}{6}-\left(\frac{11}{14}-\frac{2}{21}\right)$; 7) $\frac{23}{36}-\left(\frac{2}{9}+\frac{1}{6}\right)$; 8) $\frac{3}{10}+\left(\frac{5}{6}-\frac{2}{15}\right)$.

Question

Вопрос: $Фото задания: Задание 34. Вычислите. А. 1) $\frac{11}{12}-\left(\frac{1}{3}+\frac{1}{4}\right)$; 2)…$ Фото задания

Accepted Answer

$\frac{11}{12}-\left(\frac{1}{3}+\frac{1}{4}\right)=\frac{11}{12}-\frac{7}{12}=\frac{1}{3}$.
$\frac{7}{24}+\left(\frac{1}{2}+\frac{1}{2}\right)=\frac{7}{24}+1=\frac{31}{24}$.
$\frac{7}{15}-\left(\frac{2}{3}-\frac{1}{5}\right)=\frac{7}{15}-\left(\frac{10}{15}-\frac{3}{15}\right)=0$.
$\frac{13}{21}+\left(\frac{2}{3}-\frac{3}{7}\right)=\frac{13}{21}+\left(\frac{14}{21}-\frac{9}{21}\right)=\frac{18}{21}=\frac{6}{7}$.
$\frac{2}{9}+\left(\frac{5}{18}+\frac{5}{12}\right)=\frac{8}{36}+\left(\frac{10}{36}+\frac{15}{36}\right)=\frac{33}{36}=\frac{11}{12}$.
$\frac{5}{6}-\left(\frac{11}{14}-\frac{2}{21}\right)=\frac{35}{42}-\left(\frac{33}{42}-\frac{4}{42}\right)=\frac{6}{42}=\frac{1}{7}$.
$\frac{23}{36}-\left(\frac{2}{9}+\frac{1}{6}\right)=\frac{23}{36}-\left(\frac{8}{36}+\frac{6}{36}\right)=\frac{9}{36}=\frac{1}{4}$.
$\frac{3}{10}+\left(\frac{5}{6}-\frac{2}{15}\right)=\frac{3}{10}+\left(\frac{25}{30}-\frac{4}{30}\right)=1$.

Ответ: