Задание 34. Вычислите. Б. 1) $\frac{5}{6}-\frac{3}{8}+\left(\frac{5}{12}+\frac{1}{24}\right)$; 2) $\frac{1}{6}+\frac{3}{10}+\left(\frac{3}{5}-\frac{7}{30}\right)$; 3) $\left(\frac{3}{8}-\frac{1}{12}\right)+\left(\frac{7}{24}-\frac{3}{16}\right)+\frac{1}{6}$; 4) $\frac{19}{20}-\left(\frac{2}{5}+\frac{1}{4}\right)-\left(\frac{3}{10}-\frac{1}{8}\right)$.

Question

Вопрос: $Фото задания: Задание 34. Вычислите. Б. 1) $\frac{5}{6}-\frac{3}{8}+\left(\frac{5}{12}+\frac{1}{24}\right)$; 2)…$ Фото задания

Accepted Answer

$\frac{5}{6}-\frac{3}{8}+\left(\frac{5}{12}+\frac{1}{24}\right)=\frac{20}{24}-\frac{9}{24}+\frac{10}{24}+\frac{1}{24}=\frac{22}{24}=\frac{11}{12}$.
$\frac{1}{6}+\frac{3}{10}+\left(\frac{3}{5}-\frac{7}{30}\right)=\frac{5}{30}+\frac{9}{30}+\frac{11}{30}=\frac{25}{30}=\frac{5}{6}$.
$\left(\frac{3}{8}-\frac{1}{12}\right)+\left(\frac{7}{24}-\frac{3}{16}\right)+\frac{1}{6}=\frac{7}{24}+\frac{5}{48}+\frac{8}{48}=\frac{27}{48}=\frac{9}{16}$.
$\frac{19}{20}-\left(\frac{2}{5}+\frac{1}{4}\right)-\left(\frac{3}{10}-\frac{1}{8}\right)=\frac{19}{20}-\frac{13}{20}-\frac{7}{40}=\frac{12}{40}-\frac{7}{40}=\frac{1}{8}$.

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