Вопрос:

Задание 39. Найдите разность.

Ответ:

Задание 39. Найдите разность.



  1. \(1\frac{3}{4} - \frac{5}{8} = 1\frac{6}{8} - \frac{5}{8} = 1\frac{1}{8}\)

  2. \(2\frac{6}{7} - \frac{3}{14} = 2\frac{12}{14} - \frac{3}{14} = 2\frac{9}{14}\)

  3. \(\frac{8}{9} - \frac{5}{18} = \frac{16}{18} - \frac{5}{18} = \frac{11}{18}\)

  4. \(4\frac{11}{15} - \frac{3}{5} = 4\frac{11}{15} - \frac{9}{15} = 4\frac{2}{15}\)

  5. \(3\frac{7}{12} - \frac{1}{4} = 3\frac{7}{12} - \frac{3}{12} = 3\frac{4}{12} = 3\frac{1}{3}\)

  6. \(3\frac{23}{25} - \frac{4}{5} = 3\frac{23}{25} - \frac{20}{25} = 3\frac{3}{25}\)

  7. \(4\frac{16}{21} - 1\frac{5}{7} = 4\frac{16}{21} - 1\frac{15}{21} = 3\frac{1}{21}\)

  8. \(6\frac{5}{12} - 1\frac{7}{24} = 6\frac{10}{24} - 1\frac{7}{24} = 5\frac{3}{24} = 5\frac{1}{8}\)

  9. \(3\frac{5}{6} - 2\frac{2}{3} = 3\frac{5}{6} - 2\frac{4}{6} = 1\frac{1}{6}\)

  10. \(2\frac{7}{8} - \frac{7}{16} = 2\frac{14}{16} - \frac{7}{16} = 2\frac{7}{16}\)

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