Задание 39. Найдите разность. A.

Решение:

1. \(1 \frac{3}{4} - \frac{5}{8} = \frac{7}{4} - \frac{5}{8} = \frac{14}{8} - \frac{5}{8} = \frac{9}{8} = 1 \frac{1}{8}\)
2. \(2 \frac{6}{7} - \frac{3}{14} = 2 \frac{12}{14} - \frac{3}{14} = 2 \frac{9}{14}\)
3. \(5 \frac{8}{9} - \frac{5}{18} = 5 \frac{16}{18} - \frac{5}{18} = 5 \frac{11}{18}\)
4. \(4 \frac{11}{15} - \frac{3}{5} = 4 \frac{11}{15} - \frac{9}{15} = 4 \frac{2}{15}\)
5. \(3 \frac{7}{12} - \frac{1}{4} = 3 \frac{7}{12} - \frac{3}{12} = 3 \frac{4}{12} = 3 \frac{1}{3}\)
6. \(3 \frac{23}{25} - \frac{4}{5} = 3 \frac{23}{25} - \frac{20}{25} = 3 \frac{3}{25}\)
7. \(4 \frac{16}{21} - 1 \frac{5}{7} = 4 \frac{16}{21} - 1 \frac{15}{21} = 3 \frac{1}{21}\)
8. \(6 \frac{5}{12} - 1 \frac{7}{24} = 6 \frac{10}{24} - 1 \frac{7}{24} = 5 \frac{3}{24} = 5 \frac{1}{8}\)
9. \(3 \frac{5}{6} - 2 \frac{2}{3} = 3 \frac{5}{6} - 2 \frac{4}{6} = 1 \frac{1}{6}\)
10. \(2 \frac{7}{8} - 2 \frac{7}{16} = 2 \frac{14}{16} - 2 \frac{7}{16} = \frac{7}{16}\)

Ответ: 1) \(1 \frac{1}{8}\); 2) \(2 \frac{9}{14}\); 3) \(5 \frac{11}{18}\); 4) \(4 \frac{2}{15}\); 5) \(3 \frac{1}{3}\); 6) \(3 \frac{3}{25}\); 7) \(3 \frac{1}{21}\); 8) \(5 \frac{1}{8}\); 9) \(1 \frac{1}{6}\); 10) \(\frac{7}{16}\)