Ответ:
- \(\frac{2}{8}=\frac{1}{4}\)
- \(\frac{3}{18}=\frac{1}{6}\)
- \(\frac{11}{44}=\frac{1}{4}\)
- \(\frac{40}{100}=\frac{2}{5}\)
- \(\frac{6}{42}=\frac{1}{7}\)
- \(\frac{12}{36}=\frac{1}{3}\)
- \(\frac{28}{70}=\frac{2}{5}\)
- \(\frac{15}{30}=\frac{1}{2}\)
- \(\frac{11}{121}=\frac{1}{11}\)
- \(\frac{14}{42}=\frac{1}{3}\)
- \(\frac{12}{48}=\frac{1}{4}\)
- \(\frac{16}{32}=\frac{1}{2}\)
- \(\frac{15}{45}=\frac{1}{3}\)
- \(\frac{24}{72}=\frac{1}{3}\)
- \(\frac{25}{125}=\frac{1}{5}\)
- \(\frac{12}{240}=\frac{1}{20}\)
- \(\frac{15}{60}=\frac{1}{4}\)
- \(\frac{17}{51}=\frac{1}{3}\)
- \(\frac{16}{48}=\frac{1}{3}\)
- \(\frac{25}{200}=\frac{1}{8}\)
- \(\frac{2a}{4}=\frac{a}{2}\)
- \(\frac{2a}{3a}=\frac{2}{3}\)
- \(\frac{3x}{9x}=\frac{1}{3}\)
- \(\frac{7b}{15b}=\frac{7}{15}\)
- \(\frac{16x}{12x}=\frac{4}{3}\)
- \(\frac{6a}{3ab}=\frac{2}{b}\)
- \(\frac{5xy}{10y}=\frac{x}{2}\)
- \(\frac{21b}{14bc}=\frac{3}{2c}\)
- \(\frac{100ac}{25abc}=\frac{4}{b}\)
- \(\frac{2x}{x^2}=\frac{2}{x}\)
- \(\frac{4y^2}{8y}=\frac{y}{2}\)
- \(\frac{3a^3}{15a}=\frac{a^2}{5}\)
- \(\frac{28c^4}{14c^5}=\frac{2}{c}\)
- \(\frac{-10ab}{20ba}=-\frac{1}{2}\)
- \(\frac{-9xy}{14xy^2}=-\frac{9}{14y}\)
- \(\frac{-8a^2b^2}{-40ab}=\frac{ab}{5}\)
- \(\frac{a^2b^3}{3a^3b^3}=\frac{1}{3a}\)
- \(\frac{8ab}{16abc}=\frac{1}{2c}\)
- \(\frac{-2ab}{-4ab^2}=\frac{1}{2b}\)
- \(\frac{30x^2y^3}{15xy}=2xy^2\)
- \(\frac{2(x-3)}{5(x-3)}=\frac{2}{5}\)
- \(\frac{-7(b+2)}{3(b+2)}=-\frac{7}{3}\)
- \(\frac{3(x-2)}{9(x-2)}=\frac{1}{3}\)
- \(\frac{10(a-4)}{5(a-4)}=2\)
- \(\frac{4b(b-1)}{8(b-1)}=\frac{b}{2}\)
- \(\frac{11x^2(x-2)}{3x(x-2)}=\frac{11x}{3}\)
- \(\frac{x^3(5-x)}{2(5-x)}=\frac{x^3}{2}\)
- \(\frac{6(2+a)}{(a-3)(2+a)}=\frac{6}{a-3}\)
- \(\frac{b^2(b-5)}{(b-3)(b-5)}=\frac{b^2}{b-3}\)
- \(\frac{3p(p-4)}{(p+1)(p-4)}=\frac{3p}{p+1}\)
- \(\frac{10(y-7)}{(y-7)(y+3)}=\frac{10}{y+3}\)
- \(\frac{20b(1-b)}{30b^2(1-b)}=\frac{2}{3b}\)
- \(\frac{21x(x+y)}{28y(x+y)}=\frac{3x}{4y}\)
- \(\frac{15ab(a+5)}{45a^2(a+5)}=\frac{b}{3a}\)
- \(\frac{3b(a^3+1)}{2a(a^3+1)}=\frac{3b}{2a}\)
- \(\frac{(a+b)^2}{5(a+b)}=\frac{a+b}{5}\)
- \(\frac{(a+3)^2}{a(a+3)}=\frac{a+3}{a}\)
- \(\frac{2(x-6)}{(x-6)^2}=\frac{2}{x-6}\)
- \(\frac{y(x+2)}{(x+2)^2}=\frac{y}{x+2}\)
- \(\frac{(x-y)^2}{(x-y)(x+y)}=\frac{x-y}{x+y}\)
Во всех пунктах выполнено сокращение на общий ненулевой множитель.
