Решение:
- \( x + \frac{x}{9} = -\frac{10}{3} \)
\( \frac{9x + x}{9} = -\frac{10}{3} \)
\( \frac{10x}{9} = -\frac{10}{3} \)
\( 10x \cdot 3 = -10 \cdot 9 \)
\( 30x = -90 \)
\( x = \frac{-90}{30} \)
\( x = -3 \) - \( x - \frac{x}{7} = 6 \)
\( \frac{7x - x}{7} = 6 \)
\( \frac{6x}{7} = 6 \)
\( 6x = 6 \cdot 7 \)
\( 6x = 42 \)
\( x = \frac{42}{6} \)
\( x = 7 \) - \( x + \frac{x}{5} = -\frac{12}{5} \)
\( \frac{5x + x}{5} = -\frac{12}{5} \)
\( \frac{6x}{5} = -\frac{12}{5} \)
\( 6x = -12 \)
\( x = \frac{-12}{6} \)
\( x = -2 \) - \( x - \frac{x}{12} = \frac{11}{3} \)
\( \frac{12x - x}{12} = \frac{11}{3} \)
\( \frac{11x}{12} = \frac{11}{3} \)
\( 11x \cdot 3 = 11 \cdot 12 \)
\( 33x = 132 \)
\( x = \frac{132}{33} \)
\( x = 4 \) - \( x + \frac{x}{2} = -9 \)
\( \frac{2x + x}{2} = -9 \)
\( \frac{3x}{2} = -9 \)
\( 3x = -9 \cdot 2 \)
\( 3x = -18 \)
\( x = \frac{-18}{3} \)
\( x = -6 \) - \( x - \frac{x}{11} = \frac{50}{11} \)
\( \frac{11x - x}{11} = \frac{50}{11} \)
\( \frac{10x}{11} = \frac{50}{11} \)
\( 10x = 50 \)
\( x = \frac{50}{10} \)
\( x = 5 \) - \( 6 + \frac{x}{2} = \frac{x+3}{5} \)
\( \frac{30 + 5x}{5} = \frac{x+3}{5} \)
\( 30 + 5x = x+3 \)
\( 5x - x = 3 - 30 \)
\( 4x = -27 \)
\( x = -\frac{27}{4} \) - \( -4 + \frac{x}{5} = \frac{x+4}{2} \)
\( \frac{-20 + x}{5} = \frac{x+4}{2} \)
\( 2(-20 + x) = 5(x+4) \)
\( -40 + 2x = 5x + 20 \)
\( 2x - 5x = 20 + 40 \)
\( -3x = 60 \)
\( x = \frac{60}{-3} \)
\( x = -20 \) - \( 1 + \frac{x}{5} = \frac{x+9}{7} \)
\( \frac{5 + x}{5} = \frac{x+9}{7} \)
\( 7(5+x) = 5(x+9) \)
\( 35 + 7x = 5x + 45 \)
\( 7x - 5x = 45 - 35 \)
\( 2x = 10 \)
\( x = \frac{10}{2} \)
\( x = 5 \)
Ответ: 1) -3; 2) 7; 3) -2; 4) 4; 5) -6; 6) 5; 7) -27/4; 8) -20; 9) 5.