Ответ:
По правилу \((x^m)^n=x^{mn}\): \(\dfrac{(x^2)^4x^5}{x^7}=x^{2\cdot4+5-7}=x^6\). При \(x=2\): \(2^6=64\).
\(\dfrac{(y^5)^7y^2}{y^{36}}=y^{5\cdot7+2-36}=y\). При \(y=7\): \(7\).
\(\dfrac{(a^4)^5a^7}{a^{29}}=a^{4\cdot5+7-29}=a^{-2}=\dfrac{1}{a^2}\). При \(a=5\): \(\dfrac{1}{25}\).
\(\dfrac{(b^2)^7b^3}{b^{18}}=b^{2\cdot7+3-18}=b^{-1}=\dfrac{1}{b}\). При \(b=4\): \(\dfrac{1}{4}\).
Ответ: 1) 64; 2) 7; 3) \(\dfrac{1}{25}\); 4) \(\dfrac{1}{4}\).
