Решение задания 1:
a) \(\frac{k^6}{7-m} \cdot \frac{14-2m}{11k^5}\) = \(\frac{k^6 \cdot 2(7-m)}{(7-m) \cdot 11k^5}\) = \(\frac{2k}{11}\)
б) \(\frac{54k^{13}}{68g^4}:(-\frac{18k^9}{34g^2})\) = \(\frac{54k^{13} \cdot 34g^2}{68g^4 \cdot (-18k^9)}\) = - \(\frac{3k^4}{2g^2}\)
Ответ: a) \(\frac{2k}{11}\); б) - \(\frac{3k^4}{2g^2}\)