Краткое пояснение: Заполним таблицу истинности для логического выражения G = ¬(T ∨ B) ∧ (B ∨ C), используя значения T, B и C.
Пошаговое решение:
- Строка 1: T=0, B=0, C=0
- T ∨ B = 0 ∨ 0 = 0
- ¬(T ∨ B) = ¬0 = 1
- B ∨ C = 0 ∨ 0 = 0
- G = 1 ∧ 0 = 0
- Строка 2: T=0, B=0, C=1
- T ∨ B = 0 ∨ 0 = 0
- ¬(T ∨ B) = ¬0 = 1
- B ∨ C = 0 ∨ 1 = 1
- G = 1 ∧ 1 = 1
- Строка 3: T=0, B=1, C=0
- T ∨ B = 0 ∨ 1 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 1 ∨ 0 = 1
- G = 0 ∧ 1 = 0
- Строка 4: T=0, B=1, C=1
- T ∨ B = 0 ∨ 1 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 1 ∨ 1 = 1
- G = 0 ∧ 1 = 0
- Строка 5: T=1, B=0, C=0
- T ∨ B = 1 ∨ 0 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 0 ∨ 0 = 0
- G = 0 ∧ 0 = 0
- Строка 6: T=1, B=0, C=1
- T ∨ B = 1 ∨ 0 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 0 ∨ 1 = 1
- G = 0 ∧ 1 = 0
- Строка 7: T=1, B=1, C=0
- T ∨ B = 1 ∨ 1 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 1 ∨ 0 = 1
- G = 0 ∧ 1 = 0
- Строка 8: T=1, B=1, C=1
- T ∨ B = 1 ∨ 1 = 1
- ¬(T ∨ B) = ¬1 = 0
- B ∨ C = 1 ∨ 1 = 1
- G = 0 ∧ 1 = 0
Итоговая таблица:
| T | B | C | T ∨ B | ¬(T ∨ B) | B ∨ C | G |
| 0 | 0 | 0 | 0 | 1 | 0 | 0 |
| 0 | 0 | 1 | 0 | 1 | 1 | 1 |
| 0 | 1 | 0 | 1 | 0 | 1 | 0 |
| 0 | 1 | 1 | 1 | 0 | 1 | 0 |
| 1 | 0 | 0 | 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 1 | 0 | 1 | 0 |
| 1 | 1 | 0 | 1 | 0 | 1 | 0 |
| 1 | 1 | 1 | 1 | 0 | 1 | 0 |