Заполним таблицу, используя правила сложения и вычитания дробей с разными знаменателями:
$$1\frac{8}{9} - \frac{7}{12} = \frac{8 \cdot 4}{9 \cdot 4} - \frac{7 \cdot 3}{12 \cdot 3} = \frac{32}{36} - \frac{21}{36} = \frac{11}{36}$$
$$7 \frac{5}{5} - 3\frac{2}{5} = 4\frac{5}{5} - 3\frac{2}{5} = 1\frac{3}{5}$$
$$\frac{13}{12} - \frac{13}{20} = \frac{13 \cdot 5}{12 \cdot 5} - \frac{13 \cdot 3}{20 \cdot 3} = \frac{65}{60} - \frac{39}{60} = \frac{26}{60} = \frac{13}{30}$$
$$8\frac{7}{12} - 5 = 3\frac{7}{12}$$
$$\frac{1}{6} + \frac{3}{8} = \frac{1 \cdot 4}{6 \cdot 4} + \frac{3 \cdot 3}{8 \cdot 3} = \frac{4}{24} + \frac{9}{24} = \frac{13}{24}$$
$$14 - 13\frac{17}{18} = \frac{14}{1} - \frac{251}{18} = \frac{14 \cdot 18}{1 \cdot 18} - \frac{251}{18} = \frac{252}{18} - \frac{251}{18} = \frac{1}{18}$$
$$\frac{16}{21} - \frac{7}{15} = \frac{16 \cdot 5}{21 \cdot 5} - \frac{7 \cdot 7}{15 \cdot 7} = \frac{80}{105} - \frac{49}{105} = \frac{31}{105}$$
$$4\frac{7}{12} - 3 = 1\frac{7}{12}$$
$$9\frac{20}{33} - 7\frac{17}{44} = 9\frac{20 \cdot 4}{33 \cdot 4} - 7\frac{17 \cdot 3}{44 \cdot 3} = 9\frac{80}{132} - 7\frac{51}{132} = 2\frac{29}{132}$$
$$14\frac{5}{14} - 5\frac{23}{21} = 14\frac{5 \cdot 3}{14 \cdot 3} - 5\frac{23 \cdot 2}{21 \cdot 2} = 14\frac{15}{42} - 5\frac{46}{42} = 13\frac{57}{42} - 5\frac{46}{42} = 8\frac{11}{42}$$
$$4\frac{9}{20} + 3\frac{13}{30} = 4\frac{9 \cdot 3}{20 \cdot 3} + 3\frac{13 \cdot 2}{30 \cdot 2} = 4\frac{27}{60} + 3\frac{26}{60} = 7\frac{53}{60}$$
$$20 - \frac{17}{20} = \frac{20 \cdot 20}{1 \cdot 20} - \frac{17}{20} = \frac{400}{20} - \frac{17}{20} = \frac{383}{20} = 19\frac{3}{20}$$