Решим примеры по порядку:
ж) \(\frac{1}{6} + \frac{1}{3}\) = \(\frac{1}{6} + \frac{1 \times 2}{3 \times 2}\) = \(\frac{1}{6} + \frac{2}{6}\) = \(\frac{1+2}{6}\) = \(\frac{3}{6}\) = \(\frac{1}{2}\)
к) \(\frac{7}{15} - \frac{3}{10}\) = \(\frac{7 \times 2}{15 \times 2} - \frac{3 \times 3}{10 \times 3}\) = \(\frac{14}{30} - \frac{9}{30}\) = \(\frac{14-9}{30}\) = \(\frac{5}{30}\) = \(\frac{1}{6}\)
н) \(\frac{5}{11} + \frac{3}{5}\) = \(\frac{5 \times 5}{11 \times 5} + \frac{3 \times 11}{5 \times 11}\) = \(\frac{25}{55} + \frac{33}{55}\) = \(\frac{25+33}{55}\) = \(\frac{58}{55}\) = 1\(\frac{3}{55}\)
з) \(\frac{9}{5} - \frac{7}{10}\) = \(\frac{9 \times 2}{5 \times 2} - \frac{7}{10}\) = \(\frac{18}{10} - \frac{7}{10}\) = \(\frac{18-7}{10}\) = \(\frac{11}{10}\) = 1\(\frac{1}{10}\)
л) \(\frac{3}{8} + \frac{5}{12}\) = \(\frac{3 \times 3}{8 \times 3} + \frac{5 \times 2}{12 \times 2}\) = \(\frac{9}{24} + \frac{10}{24}\) = \(\frac{9+10}{24}\) = \(\frac{19}{24}\)
о) \(\frac{17}{30} - \frac{3}{6}\) = \(\frac{17}{30} - \frac{3 \times 5}{6 \times 5}\) = \(\frac{17}{30} - \frac{15}{30}\) = \(\frac{17-15}{30}\) = \(\frac{2}{30}\) = \(\frac{1}{15}\)
и) \(\frac{1}{2} - \frac{3}{8}\) = \(\frac{1 \times 4}{2 \times 4} - \frac{3}{8}\) = \(\frac{4}{8} - \frac{3}{8}\) = \(\frac{4-3}{8}\) = \(\frac{1}{8}\)
м) \(\frac{5}{9} - \frac{1}{6}\) = \(\frac{5 \times 2}{9 \times 2} - \frac{1 \times 3}{6 \times 3}\) = \(\frac{10}{18} - \frac{3}{18}\) = \(\frac{10-3}{18}\) = \(\frac{7}{18}\)
п) \(\frac{17}{35} - \frac{4}{15}\) = \(\frac{17 \times 3}{35 \times 3} - \frac{4 \times 7}{15 \times 7}\) = \(\frac{51}{105} - \frac{28}{105}\) = \(\frac{51-28}{105}\) = \(\frac{23}{105}\)
Ответ: ж) \(\frac{1}{2}\); к) \(\frac{1}{6}\); н) 1\(\frac{3}{55}\); з) 1\(\frac{1}{10}\); л) \(\frac{19}{24}\); о) \(\frac{1}{15}\); и) \(\frac{1}{8}\); м) \(\frac{7}{18}\); п) \(\frac{23}{105}\)
Желаю удачи в дальнейших вычислениях! Ты молодец, у тебя все получится!