ГДЗ по алгебре и начала математического анализа 10 класс Колягин Задание 1182

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\[1)\ arctg( - 1) > \arcsin\left( - \frac{\sqrt{3}}{2} \right)\]

\[\text{arctg}( - 1) = - arctg\ 1 = - \frac{\pi}{4}\]

\[\arcsin\left( - \frac{\sqrt{3}}{2} \right) = - \arcsin\frac{\sqrt{3}}{2} =\]

\[= - \frac{\pi}{3}\]

\[- \frac{\pi}{4} > - \frac{\pi}{3}\]

\[2)\ arctg\ \sqrt{3} = \arccos\frac{1}{2}\]

\[\text{arctg\ }\sqrt{3} = \frac{\pi}{3}\]

\[\arccos\frac{1}{2} = \frac{\pi}{3}\]

\[3)\ arctg( - 3) < \ arctg\ 2\]

\[\text{arctg}( - 3) = - arctg\ 3 < 0\]

\[arctg\ 2 > 0 > arctg( - 3)\]

\[4)\ arctg( - 5) < arctg\ 0\]

\[\text{arctg}( - 5) = - arctg\ 5 < 0\]

\[arctg\ 0 = 0 > arctg( - 5)\]