ГДЗ по алгебре и начала математического анализа 10 класс Колягин Задание 602

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\[1)\ \sqrt{x} = 2\]

\[\left( \sqrt{x} \right)^{2} = 2^{2}\]

\[x = 4.\]

\[2)\ \sqrt{x} = 7\]

\[\left( \sqrt{x} \right)^{2} = 7^{2}\]

\[x = 49.\]

\[3)\ \sqrt[3]{x} = 2\]

\[\left( \sqrt[3]{x} \right)^{3} = 2^{3}\]

\[x = 8.\]

\[4)\ \sqrt[3]{x} = - 3\]

\[\left( \sqrt[3]{x} \right)^{3} = ( - 3)^{3}\]

\[x = - 27.\]

\[5)\ \sqrt[3]{1 - 3x} = 0\]

\[\left( \sqrt[3]{1 - 3x} \right)^{3} = 0^{3}\]

\[1 - 3x = 0\]

\[3x = 1\]

\[x = \frac{1}{3}.\]

\[6)\ \sqrt[4]{x} = 1\]

\[\left( \sqrt[4]{x} \right)^{4} = 1^{4}\]

\[x = 1.\]

\[7)\ \sqrt[4]{2 - x} = 0\]

\[\left( \sqrt[4]{2 - x} \right)^{4} = 0^{4}\]

\[2 - x = 0\]

\[x = 2.\]