ГДЗ по алгебре и начала математического анализа 10 класс Колягин Задание 927

\[\boxed{\mathbf{927.}}\]

\[\mathbf{а)\ }a_{d} = \frac{180{^\circ}}{3} = 60{^\circ}\]

\[a_{r} = \frac{\pi \bullet 60}{180} = \frac{\pi}{3}\]

\[\textbf{б)}\ a_{d1} = 90{^\circ}\ \ и\ \ a_{d2} =\]

\[= \frac{180{^\circ} - 90{^\circ}}{2} = \frac{90{^\circ}}{2} = 45{^\circ}\]

\[a_{r1} = \frac{\pi \bullet 90}{180} = \frac{\pi}{2}\text{\ \ }и\ \]

\[\ a_{r2} = \frac{\pi \bullet 45}{180} = \frac{\pi}{4}\]

\[\textbf{в)}\ a_{d} = \frac{1}{4} \bullet (4 - 2) \bullet 180{^\circ} =\]

\[= 2 \bullet 45 = 90{^\circ}\]

\[a_{r} = \frac{\pi \bullet 90}{180} = \frac{\pi}{2}\]