ГДЗ по алгебре и начала математического анализа 10 класс Алимов Задание 132

\[\boxed{\mathbf{132.}}\]

\[1)\ y = 2x - 1\]

\[2x = y + 1\]

\[x = \frac{y + 1}{2}\]

\[Ответ:\ \ y = \frac{1}{2}(x + 1).\]

\[2)\ y = - 5x + 4\]

\[5x = 4 - y\]

\[x = \frac{4 - y}{5}\]

\[Ответ:\ \ y = \frac{1}{5}(4 - x).\]

\[3)\ y = \frac{1}{3}x - \frac{2}{3}\]

\[\frac{1}{3}x = y + \frac{2}{3}\]

\[x = 3y + 2\]

\[Ответ:\ \ y = 3x + 2.\]

\[4)\ y = \frac{3x - 1}{2}\]

\[2y = 3x - 1\]

\[3x = 2y + 1\]

\[x = \frac{2y + 1}{3}\]

\[Ответ:\ \ y = \frac{1}{3}(2x + 1).\]

\[5)\ y = x^{3} + 1\]

\[x^{3} = y - 1\]

\[x = \sqrt[3]{y - 1}\]

\[Ответ:\ \ y = \sqrt[3]{x - 1}.\]

\[6)\ y = x^{3} - 3\]

\[x^{3} = y + 3\]

\[x = \sqrt[3]{y + 3}\]

\[Ответ:\ \ y = \sqrt[3]{x + 3}.\]