ГДЗ по алгебре и начала математического анализа 10 класс Алимов Задание 408

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\[1)\ \frac{\pi}{6} = \left( \frac{\pi}{6} \bullet \frac{180}{\pi} \right)^{{^\circ}} = \left( \frac{180}{6} \right)^{{^\circ}} =\]

\[= 30{^\circ}\]

\[2)\ \frac{\pi}{9} = \left( \frac{\pi}{9} \bullet \frac{180}{\pi} \right)^{{^\circ}} = \left( \frac{180}{9} \right)^{{^\circ}} =\]

\[= 20{^\circ}\]

\[3)\ \frac{3}{4}\pi = \left( \frac{3\pi}{4} \bullet \frac{180}{\pi} \right)^{{^\circ}} =\]

\[= \left( \frac{3 \bullet 180}{4} \right)^{{^\circ}} = (3 \bullet 45)^{{^\circ}} = 135^{{^\circ}}\]

\[4)\ 2 = \left( 2 \bullet \frac{180}{\pi} \right)^{{^\circ}} = \left( \frac{360}{\pi} \right)^{{^\circ}}\]

\[5)\ 3 = \left( 3 \bullet \frac{180}{\pi} \right)^{{^\circ}} = \left( \frac{540}{\pi} \right)^{{^\circ}}\]

\[6)\ 0,36 = \left( 0,36 \bullet \frac{180}{\pi} \right)^{{^\circ}} =\]

\[= \left( \frac{64,8}{\pi} \right)^{{^\circ}}\]