ГДЗ по алгебре и начала математического анализа 10 класс Алимов Задание 613

\[\boxed{\mathbf{613}\mathbf{.}}\]

\[3\ tg\ x - \sqrt{3} = 0\]

\[3\ tg\ x = \sqrt{3}\]

\[tg\ x = \frac{\sqrt{3}}{3}\]

\[x = arctg\frac{\sqrt{3}}{3} + \pi n\]

\[x = \frac{\pi}{6} + \pi n.\]

\[1)\ x_{\min} = \frac{\pi}{6} + 0 = \frac{\pi}{6}\]

\[2)\ x_{\max} = \frac{\pi}{6} - \pi = - \frac{5\pi}{6}\]