ГДЗ по алгебре и начала математического анализа 11 класс Алимов Задание 10

\[\boxed{\mathbf{10}\mathbf{.}}\]

\[1)\ \sqrt{63} \bullet \sqrt{28} = \sqrt{63 \bullet 28} =\]

\[= \sqrt{7 \bullet 9 \bullet 7 \bullet 4} = 7 \bullet 3 \bullet 2 = 42\]

\[2)\ \sqrt{20} \bullet \sqrt{5} = \sqrt{20 \bullet 5} =\]

\[= \sqrt{4 \bullet 5 \bullet 5} = 2 \bullet 5 = 10;\]

\[3)\ \sqrt{50}\ :\sqrt{8} = \sqrt{\frac{50}{8}} = \sqrt{\frac{25}{4}} =\]

\[= \frac{5}{2} = 2,5\]

\[4)\ \sqrt{12}\ :\sqrt{27} = \sqrt{\frac{12}{27}} = \sqrt{\frac{4}{9}} = \frac{2}{3}\]