ГДЗ по алгебре и начала математического анализа 11 класс Алимов Задание 443

\[\boxed{\mathbf{443.}}\]

\[1)\ \frac{\pi}{2} - a\]

\[0 < a < \frac{\pi}{2}\]

\[- \frac{\pi}{2} < - a < 0\]

\[0 < \frac{\pi}{2} - a < \frac{\pi}{2}\]

\[в\ I\ четверти.\]

\[2)\ a - \pi\]

\[0 < a < \frac{\pi}{2}\]

\[- \pi < a - \pi < - \frac{\pi}{2}\ \ \ \ \ | + 2\pi\]

\[\pi < a - \pi < \frac{3\pi}{2}\]

\[в\ III\ четверти.\]

\[3)\ \frac{3\pi}{2} - a\]

\[0 < a < \frac{\pi}{2}\]

\[- \frac{\pi}{2} < - a < 0\]

\[\pi < \frac{3\pi}{2} - a < \frac{3\pi}{2}\]

\[\ в\ III\ четверти.\]

\[4)\ \frac{\pi}{2} + a\]

\[0 < a < \frac{\pi}{2}\]

\[\frac{\pi}{2} < \frac{\pi}{2} + a < \pi\]

\[во\text{\ II\ }четверти.\]

\[5)\ a - \frac{\pi}{2}\]

\[0 < a < \frac{\pi}{2}\]

\[- \frac{\pi}{2} < a - \frac{\pi}{2} < 0\ \ \ \ \ | + 2\pi\]

\[\frac{3\pi}{2} < a - \frac{\pi}{2} < 2\pi\]

\[в\ IV\ четверти.\]

\[6)\ \pi - a\]

\[0 < a < \frac{\pi}{2}\]

\[- \frac{\pi}{2} < - a < 0\]

\[\frac{\pi}{2} < \pi - a < \pi\]

\[во\text{\ II\ }четверти.\]