ГДЗ по алгебре 7 класс Макарычев ФГОС Задание 885

\[\boxed{\text{885.}\text{\ }еуроки - ответы\ на\ пятёрку}\]

\[\textbf{а)}\ (b - 2)(b + 2)\left( b^{2} + 4 \right) = \left( b^{2} - 4 \right)\left( b^{2} + 4 \right) = b^{4} - 16\]

\[\textbf{б)}\ (3 - y)(3 + y)\left( 9 + y^{2} \right) = \left( 9 - y^{2} \right)\left( 9 + y^{2} \right) = 81 - y^{4}\]

\[\textbf{в)}\ \left( a^{2} + 1 \right)(a + 1)(a - 1) = \left( a^{2} + 1 \right)\left( a^{2} - 1 \right) = a^{4} - 1\]

\[\textbf{г)}\ \left( c^{4} + 1 \right)\left( c^{2} + 1 \right)\left( c^{2} - 1 \right) = \left( c^{4} + 1 \right)\left( c^{4} - 1 \right) = c^{8} - 1\]

\[\textbf{д)}\ (x - 3)^{2}(x + 3)^{2} = \left( x^{2} - 9 \right)\left( x^{2} - 9 \right) = x^{4} - 18x^{2} + 81\]

\[\textbf{е)}\ (y + 4)^{2}(y - 4)^{2} = \left( (y + 4)(y - 4) \right)^{2} = \left( y^{2} - 16 \right)^{2} = y^{4} - 32y^{2} + 256\ \]

\[\textbf{ж)}\ (a - 5)^{2}(5 + a)^{2} = \left( (a - 5)(5 + a) \right)^{2} = \left( a^{2} - 25 \right)^{2} = a^{4} - 50a^{2} + 625\]

\[\textbf{з)}\ (c + 4)^{2}(4 - c)^{2} = \left( (c + 4)(4 - c) \right)^{2} = \left( 16 - c^{2} \right)^{2} = 256 - 32c^{2} + c^{4}\]