ГДЗ по алгебре 7 класс Мерзляк Задание 792

\[\boxed{\text{792\ (792).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ x = 12 \Longrightarrow\]

\[\Longrightarrow \ \ y = - \frac{1}{6} \cdot 12 + 2 = 0\]

\[x = 6, \Longrightarrow \ y = - \frac{1}{6} \cdot 6 + 2 = 1\]

\[x = - 6 \Longrightarrow \ \ y = \frac{1}{6} \cdot 6 + 2 = 3\]

\[x = 0 \Longrightarrow \ \ y = 0 + 2 = 2\]

\[x = 1 \Longrightarrow \ \ y = - \frac{1}{6} + 2 = \frac{11}{6} =\]

\[= 1\frac{5}{6}\]

\[x = 2 \Longrightarrow \ \ y = - \frac{1}{6} \cdot 2 + 2 =\]

\[= - \frac{1}{3} + 2 = \frac{5}{3} = 1\frac{2}{3}\]

\[x = - 4 \Longrightarrow \ \ y = \frac{1}{6} \cdot 4 + 2 =\]

\[= \frac{2}{3} + 2 = 2\frac{2}{3}\]

\[x = - 3 \Longrightarrow \ y = \frac{1}{6} \cdot 3 + 2 = 2,5\]

\[2)\ y = 4:\]

\[- \frac{1}{6}x + 2 = 4\]

\[- \frac{1}{6}x = 2\ \ \]

\[x = \frac{2 \cdot 6}{- 1} = - 12.\]

\[y = 3:\ \ \]

\[- \frac{1}{6}x + 2 = 3\ \]

\[- \frac{1}{6}x = 1\ \ \]

\[x = - 6.\]

\[y = 0:\ \]

\[- \frac{1}{6}x + 2 = 0\ \ \]

\[- \frac{1}{6}x = - 2\ \]

\[x = 12.\]

\[y = - 1:\ \ \]

\[- \frac{1}{6}x + 2 = - 1\ \ \]

\[- \frac{1}{6}x = - 3\ \ \]

\[x = 18.\]