§ Задание 962
\[\boxed{\text{962\ (962).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
\[1)\ x + y = - 3\ \ \]
\[y = - 3 - x\]
| \[x\] | \[0\] | \[- 1\] |
|---|---|---|
| \[y\] | \[- 3\] | \[- 2\] |

\[2)\ 6x + y = 0\]
\[y = - 6x\]
| \[x\] | \[0\] | \[1\] |
|---|---|---|
| \[y\] | \[0\] | \[- 6\] |

\[3)\ 2x - 3y = 9\]
\[3y = 2x - 9\]
\[y = \frac{2x - 9}{3} = \frac{2}{3}x - 3\ \]
| \[x\] | \[0\] | \[3\] |
|---|---|---|
| \[y\] | \[- 3\] | \[- 1\] |









