ГДЗ по алгебре 8 класс Макарычев Задание 148

\[\boxed{\text{148\ (148).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\left( \ \frac{x^{\backslash x}}{y^{2}} - \frac{1^{\backslash y^{2}}}{x} \right)\ :\left( \frac{1^{\backslash x}}{y} + \frac{1^{\backslash y}}{x} \right) =\]

\[= \frac{x^{2} - y^{2}}{xy^{2}}\ :\frac{x + y}{\text{xy}} =\]

\[= \frac{(x - y)(x + y)}{xy^{2}} \cdot \frac{\text{xy}}{x + y} =\]

\[= \frac{x - y}{y}\]

\[= \frac{a(m + a)}{m^{3}} \cdot \frac{a^{2}}{m(m + a)} = \frac{a^{3}}{m^{4}}\]

\[\textbf{в)}\ \frac{ab + b^{2}}{3}\ :\frac{b^{3}}{3a} + \frac{a + b}{b} =\]

\[= \frac{b(a + b)}{3} \cdot \frac{3a}{b^{3}} + \frac{a + b}{b} =\]

\[= \frac{a(a + b)}{b^{2}} + \frac{a + b^{\backslash b}}{b} =\]

\[\textbf{г)}\ \frac{x - y}{x} - \frac{5y}{x^{2}} \cdot \frac{x^{2} - xy}{5y} =\]

\[= \frac{x - y}{x} - \frac{x(x + y)}{x^{2}} =\]

\[= \frac{x - y}{x} - \frac{x - y}{x} = 0\]