\[\boxed{\text{214\ (214).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{б)}\ \frac{\left( a^{2} - 9 \right)^{2}}{(3 - a)^{3}} =\]
\[= \frac{\left( (a - 3)(a + 3) \right)^{2}}{(3 - a)^{3}} =\]
\[= \frac{(a - 3)^{2} \cdot (a + 3)^{2}}{(3 - a)^{3}} =\]
\[\textbf{в)}\ \frac{8y^{3} - 1}{y - 4y^{3}} =\]
\[= \frac{(2y - 1)\left( 4y^{2} + 2y + 1 \right)}{y\left( 1 - 4y^{2} \right)} =\]
\[= \frac{(2y - 1)\left( 4y^{2} + 2y + 1 \right)}{y(1 - 2y)(1 + 2y)} =\]
\[= - \frac{4y^{2} + 2y + 1}{y(1 + 2y)}\]
\[\textbf{г)}\ \frac{5a^{2} - 3ab}{a^{2} - 0,36b^{2}} = \frac{a(5a - 3b)}{a^{2} - 0,36b^{2}} =\]
\[= \frac{5a}{a + 0,6b}\ \]