ГДЗ по алгебре 8 класс Макарычев Задание 237

\[\boxed{\text{237\ (237).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ \frac{5n^{2} + 2n + 3}{n} =\]

\[= \frac{5n^{2}}{n} + \frac{2n}{n} + \frac{3}{n} = 5n + 2 + \frac{3}{n}\]

\[n = \left\{ - 3,\ - 1,\ 1,\ 3 \right\}.\]

\[\textbf{б)}\ \frac{(n - 3)^{2}}{n} = \frac{n^{2} - 6n + 9}{n} =\]

\[= \frac{n^{2}}{n} - \frac{6n}{n} + \frac{9}{n} = n - 6 + \frac{9}{n}\]

\[n = \left\{ - 9, - 3, - 1,\ 1,\ 3,\ 9 \right\}\text{.\ }\]

\[\textbf{в)}\ \frac{3n}{n + 2} = \frac{3n + 6 - 6}{n + 2} =\]

\[= \frac{3(n + 2) - 6}{n + 2} =\]

\[= \frac{3(n + 2)}{n + 2} - \frac{6}{n + 2} = 3 - \frac{6}{n + 2}\]

\[n = \pm 1;\ \pm 4;\ 0;\ - 3;\ - 5;\ - 8.\]

\[\textbf{г)}\ \frac{7n}{n - 4} = \frac{7n - 28 + 28}{n - 4} =\]

\[= \frac{7(n - 4) + 28}{n - 4} =\]

\[= \frac{7(n - 4)}{n - 4} + \frac{28}{n - 4} = 7 + \frac{28}{n - 4}\text{\ \ }\]

\[n = 0;\ \pm 3;2;5;6;8;11;\ - 10;\]

\[18;\ - 24;32.\]