ГДЗ по алгебре 8 класс Макарычев Задание 24

\[\boxed{\text{24\ (24).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\frac{10xz}{15yz} = \frac{5z \cdot 2x}{5z \cdot 3y} = \frac{2x}{3y}\text{\ \ }\]

\[\textbf{б)}\frac{6ab^{2}}{9bc^{2}} = \frac{3b \cdot 2ab}{3b \cdot 3c^{2}} = \frac{2ab}{3c^{2}}\]

\[\textbf{в)}\frac{2ay^{3}}{- 4a^{2}b} = - \frac{2a \cdot y^{3}}{2a \cdot 2ab} = - \frac{y^{3}}{2ab}\]

\[\textbf{г)}\frac{- 6p^{2}q}{- 2q^{3}} = \frac{2q \cdot 3p^{2}}{2q \cdot q^{2}} = \frac{3p^{2}}{q^{2}}\]

\[\textbf{д)}\frac{24a^{2}c^{2}}{36ac} = \frac{12ac \cdot 2ac}{12ac \cdot 3} = \frac{2ac}{3}\]

\[\textbf{е)}\frac{63x^{2}y^{3}}{42x^{6}y^{4}} = \frac{21x^{2}y^{3} \cdot 3}{21x^{2}y^{3} \cdot 2x^{4}y} =\]

\[= \frac{3}{2x^{4}y}\]