\[\boxed{\text{27\ (27).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\textbf{а)}\frac{8^{16}}{16^{12}} = \frac{{(2^{3})}^{16}}{{(2^{4})}^{12}} = \frac{2^{48}}{2^{48}} = 1\]
\[\textbf{б)}\frac{81^{25}}{27^{33}} = \frac{\left( 3^{4} \right)^{25}}{\left( 3^{3} \right)^{33}} = \frac{3^{100}}{3^{99}} =\]
\[= 3^{1} = 3\]