ГДЗ по алгебре 8 класс Макарычев Задание 295

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Год:2021
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Задание 295

\[\boxed{\text{295\ (}\text{c}\text{).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ |2x - 8| = ?\]

\[x = - 2,5:\]

\[\left| 2 \cdot ( - 2,5) - 8 \right| = | - 5 - 8| =\]

\[= | - 13| = 13.\]

\[x = 0:\]

\[|2 \cdot 0 - 8| = |0 - 8| = | - 8| = 8.\]

\[x = 4:\]

\[|2 \cdot 4 - 8| = |8 - 8| = 0.\]

\[x = 5:\]

\[|2 \cdot 5 - 8| = |10 - 8| = 2.\]

\[x = 9,5:\]

\[|2 \cdot 9,5 - 8| = |19 - 8| = 11.\]

\[\textbf{б)}\ |6 - 12x| = ?\]

\[x = - 3:\]

\[x = \left| 6 - 12 \cdot ( - 3) \right| = |6 + 36| =\]

\[= 42.\]

\[x = - 1:\]

\[\left| 6 - 12 \cdot ( - 1) \right| = |6 + 12| = 18.\]

\[x = 0:\]

\[|6 - 12 \cdot 0| = |6 - 0| = 6.\]

\[x = 1:\]

\[|6 - 12 \cdot 1| = |6 - 12| = | - 6| =\]

\[= 6.\]

\[x = 4:\]

\[|6 - 12 \cdot 4| = |6 - 48| = | - 42| =\]

\[= 42.\]

\[\boxed{\text{295\ (}\text{н}\text{).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ |28x - 8| = ?\]

\[x = - 2,5:\]

\[\left| 28 \cdot ( - 2,5) - 8 \right| = | - 70 - 8| =\]

\[= | - 78| = 78.\]

\[x = 0:\]

\[|28 \cdot 0 - 8| = |0 - 8| = | - 8| = 8.\]

\[x = 4:\]

\[|28 \cdot 4 - 8| = |112 - 8| = |104| =\]

\[= 104.\]

\[x = 5:\]

\[|28 \cdot 5 - 8| = |140 - 8| = 132.\]

\[x = 9,5:\]

\[|28 \cdot 9,5 - 8| = |266 - 8| = 258.\]

\[\textbf{б)}\ |6 - 12x| = ?\]

\[x = - 3:\]

\[x = \left| 6 - 12 \cdot ( - 3) \right| = |6 + 36| =\]

\[= 42.\]

\[x = - 1:\]

\[\left| 6 - 12 \cdot ( - 1) \right| = |6 + 12| =\]

\[= 18.\]

\[x = 0:\]

\[|6 - 12 \cdot 0| = |6 - 0| = 6.\]

\[x = 1:\]

\[|6 - 12 \cdot 1| = |6 - 12| = | - 6| =\]

\[= 6.\]

\[x = 4:\]

\[|6 - 12 \cdot 4| = |6 - 48| = | - 42| =\]

\[= 42.\]

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