ГДЗ по алгебре 8 класс Макарычев Задание 370

\[\boxed{\text{370\ (370).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\ \sqrt{\frac{9}{64}} = \frac{\sqrt{9}}{\sqrt{64}} = \frac{3}{8}\]

\[\textbf{б)}\ \sqrt{\frac{36}{25}} = \frac{\sqrt{36}}{\sqrt{25}} = \frac{6}{5} = 1,2\]

\[\textbf{в)}\ \sqrt{\frac{121}{25}} = \frac{\sqrt{121}}{\sqrt{25}} = \frac{11}{5} = 2,2\]

\[\textbf{г)}\ \sqrt{1\frac{9}{16}} = \sqrt{\frac{25}{16}} = \frac{\sqrt{25}}{\sqrt{16}} = \frac{5}{4} =\]

\[= 1\frac{1}{4} = 1,25\]

\[\textbf{д)}\ \sqrt{2\frac{7}{81}} = \sqrt{\frac{169}{81}} = \frac{\sqrt{169}}{\sqrt{81}} =\]

\[= \frac{13}{9} = 1\frac{4}{9}\]

\[\textbf{е)}\ \sqrt{5\frac{1}{16}} = \sqrt{\frac{81}{16}} = \frac{\sqrt{81}}{\sqrt{16}} = \frac{9}{4} =\]

\[= 2\frac{1}{4} = 2,25\]