ГДЗ по алгебре 8 класс Макарычев Задание 386

\[\boxed{\text{386\ (386).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[\textbf{а)}\frac{\sqrt{2}}{\sqrt{18}} = \sqrt{\frac{2}{18}} = \sqrt{\frac{1}{9}} = \frac{1}{3}\]

\[\textbf{б)}\frac{\sqrt{23}}{\sqrt{2300}} = \sqrt{\frac{23}{2300}} = \sqrt{\frac{1}{100}} =\]

\[= \frac{1}{10}\]

\[\textbf{в)}\frac{\sqrt{52}}{\sqrt{117}} = \sqrt{\frac{52}{117}} = \sqrt{\frac{4}{9}} = \frac{2}{3}\]

\[\textbf{г)}\frac{\sqrt{12500}}{\sqrt{500}} = \sqrt{\frac{12500}{500}} = \sqrt{25} = 5\]

\[\textbf{д)}\frac{\sqrt{7,5}}{\sqrt{0,3}} = \sqrt{\frac{7,5}{0,3}} = \sqrt{25} = 5\]