ГДЗ по алгебре 8 класс Макарычев Задание 437

\[\boxed{\text{437\ (437).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ \sqrt{\frac{3}{5}} = 0,2\sqrt{15}\]

\[\sqrt{\frac{3}{5}} = \frac{1}{5}\sqrt{15}\]

\[\sqrt{\frac{3}{5}} = \sqrt{\frac{1}{25} \cdot 15}\]

\[\sqrt{\frac{3}{5}} = \sqrt{\frac{15}{25}}\]

\[\sqrt{\frac{3}{5}} = \sqrt{\frac{3}{5}\ }\text{\ \ }\]

\[Ч.т.д.\]

\[\textbf{б)}\ \sqrt{\frac{2}{a}} = \frac{1}{a}\sqrt{2a}\]

\[\sqrt{\frac{2}{a}} = \sqrt{\frac{1}{a^{2}} \cdot 2a}\]

\[\sqrt{\frac{2}{a}} = \sqrt{\frac{2a}{a^{2}}}\]

\[\sqrt{\frac{2}{a}} = \sqrt{\frac{2}{a}}\ \]

\[Ч.т.д.\ \]