ГДЗ по алгебре 8 класс Макарычев Задание 485

\[\boxed{\text{485\ (485).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\ y = \frac{\sqrt{x^{2}}}{x},\ \ x \neq 0\]

\[\left\{ \begin{matrix} y = \frac{x}{x} = 1,\ \ \ \ \ \ \ \ \ \ \ \ x > 0\ \ \\ y = \frac{x}{- x} = - 1,\ \ \ x < 0\ \ \ \ \\ \end{matrix} \right.\ \]

\[\textbf{б)}\ y = - \frac{2\sqrt{x^{2}}}{x},\ \ x \neq 0\]

\[\left\{ \begin{matrix} y = - \frac{2x}{x} = - 2,\ \ \ \ x > 0 \\ y = - \frac{2x}{- x} = 2,\ \ \ \ \ \ x < 0 \\ \end{matrix} \right.\ \]

\[\textbf{в)}\ y = x\sqrt{x^{2}}\]

\[\left\{ \begin{matrix} y = x \cdot x = x^{2},\ \ \ \ \ \ \ \ \ \ x > 0 \\ y = - x \cdot x = - x^{2},\ \ \ \ x < 0 \\ \end{matrix} \right.\ \ \]

\[\textbf{г)}\ y = - x\sqrt{x^{2}}\]

\[\left\{ \begin{matrix} y = - x \cdot x = - x^{2},\ \ \ \ x > 0 \\ y = - ( - x) \cdot x = x^{2},\ \ \ \ x < 0 \\ \end{matrix} \right.\ \]