ГДЗ по алгебре 8 класс Макарычев Задание 694

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Год:2021
Тип:учебник
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Задание 694

\[\boxed{\text{694\ (694).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[\textbf{а)}\frac{6}{|x|} = 1,5x - 2\]

\[y = \frac{6}{|x|}\]

\[x\] \[1\] \[- 1\] \[2\] \[- 2\] \[3\] \[- 3\]
\[y\] \[6\] \[6\] \[3\] \[3\] \[2\] \[2\]

\[y = 1,5x - 2\]

\[x\] \[0\] \[2\]
\[y\] \[- 2\] \[1\]

\(\ \)

\[Ответ:x = 3.\]

\[\textbf{б)}\frac{8}{|x|} = x^{2}\]

\[y = \frac{8}{|x|}\]

\[x\] \[1\] \[- 1\] \[2\] \[- 2\] \[4\] \[- 4\]
\[y\] \[8\] \[8\] \[4\] \[4\] \[2\] \[2\]

\[y = x^{2}\]

\[x\] \[0\] \[1\] \[2\] \[- 1\] \[- 2\]
\[y\] \[0\] \[1\] \[4\] \[1\] \[4\]

\(\ \)

\[Ответ:x = \pm 2.\]

\[\textbf{в)}\ \frac{3}{|x|} = x + 1\]

\[y = \frac{3}{|x|}\]

\[x\] \[1\] \[- 1\] \[2\] \[- 2\] \[3\] \[- 3\]
\[y\] \[3\] \[3\] \[1,5\] \[1,5\] \[1\] \[1\]

\[y = x + 1\]

\[x\] \[0\] \[1\]
\[y\] \[1\] \[2\]

\(\ \)

\[Ответ:x \approx 1,2.\]

\[\textbf{г)}\ x^{2} = \frac{5}{|x|}\]

\[y = x^{2}\]

\[x\] \[0\] \[1\] \[2\] \[- 1\] \[- 2\]
\[y\] \[0\] \[1\] \[4\] \[1\] \[4\]

\[y = \frac{5}{|x|}\]

\[x\] \[1\] \[2\] \[5\] \[- 1\] \[- 2\] \[- 5\]
\[y\] \[5\] \[2,5\] \[1\] \[5\] \[2,5\] \[1\]

\(\ \)

\[Ответ:x \approx \pm 1,8.\ \]

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