\[\boxed{\text{81\ (81).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]
Пояснение.
Решение.
\[\mathbf{Знаменатель\ целых\ чисел\ }\]
\[\mathbf{равен\ 1.}\]
\[\textbf{а)}\ 5^{\backslash 2} - \frac{с}{2} = \frac{10 - с}{2}\]
\[\textbf{б)}\ 5{y^{2}}^{\backslash 3} - \frac{15y^{2} - 1}{3} =\]
\[= \frac{15y^{2} - 15y^{2} + 1}{3} = \frac{1}{3}\]
\[\textbf{в)}\ a + b - \frac{a - 3}{3} =\]
\[= (a + b)^{\backslash 3} - \frac{a - 3}{3} =\]
\[= \frac{3a + 3b - a + 3}{3} =\]
\[= \frac{2a + 3b + 3}{3}\]
\[\textbf{г)}\ \frac{2b^{2} - 1}{b} - b + 5 =\]
\[= \ \frac{2b^{2} - 1}{b} - (b - 5)^{\backslash b} =\]
\[= \frac{2b^{2} - 1 - b^{2} + 5b}{b} =\]
\[= \frac{b^{2} + 5b - 1}{b}\]