ГДЗ по алгебре 8 класс Мерзляк Задание 150

\[\boxed{\text{150\ (150).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\frac{7}{a^{2}}\ :\frac{28}{a^{8}} = \frac{7 \cdot a^{8}}{a^{2} \cdot 28} = \frac{1 \cdot a^{6}}{1 \cdot 4} = \frac{a^{6}}{4}.\]

\[2)\frac{b^{9}}{8}\ :\frac{b^{3}}{48} = \frac{b^{9} \cdot 48}{8 \cdot b^{3}} = \frac{b^{6} \cdot 6}{1 \cdot 1} = 6b^{6}.\]

\[3)\frac{27}{m^{6}}\ :\frac{36}{m^{7}n^{2}} = \frac{27 \cdot m^{7}n^{2}}{m^{6} \cdot 36} =\]

\[= \frac{3 \cdot mn^{2}}{1 \cdot 4} = \frac{3mn^{2}}{4}.\]

\[4)\frac{6x^{10}}{y^{8}}\ :\left( 30x^{5}y^{2} \right) =\]

\[= \frac{6x^{10} \cdot 1}{y^{8} \cdot 30x^{5}y^{2}} = \frac{x^{5}}{y^{8} \cdot 5y^{2}} = \frac{x^{5}}{5y^{10}}.\]

\[5)\ 49m^{4}\ :\frac{21m}{n^{2}} = \frac{49m^{4} \cdot n^{2}}{21m} =\]

\[= \frac{7m^{3} \cdot n^{2}}{3} = \frac{7m^{3}n^{2}}{3}.\]

\[6)\frac{16x^{3}y^{8}}{33z^{5}}\ :\left( - \frac{10x^{2}}{55z^{6}} \right) =\]

\[= - \frac{16x^{3}y^{8} \cdot 55z^{6}}{10x^{2} \cdot 33z^{5}} =\]

\[= - \frac{8xy^{8} \cdot 5z}{5 \cdot 3} = - \frac{8xy^{8}z}{3}\text{.\ }\]