ГДЗ по алгебре 8 класс Мерзляк Задание 189

\[\boxed{\text{189\ (189).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ \frac{18y^{2} + 3y}{(3y - 1)\left( 9y^{2} + 3y + 1 \right)} -\]

\[- \frac{3y + 1^{\backslash 3y - 1}}{\left( 9y^{2} + 3y + 1 \right)} =\]

\[= \frac{\left( 18y^{2} + 3y - 9y^{2} + 1 \right)}{(3y - 1)\left( 9y^{2} + 3y + 1 \right)} =\]

\[= \frac{1}{3y - 1}\]

\[2)\ 1^{\backslash y(3y - 1)} - \frac{3y - 1^{\backslash 3y - 1}}{y} -\]

\[- \frac{5 - 6y^{\backslash y}}{3y - 1} =\]

\[= \frac{3y^{2} - y - 9y^{2} + 6y - 1 - 5y + 6y^{2}}{y(3y - 1)} =\]

\[= - \frac{1}{y(3 - 1)}\ \]

\[3)\ \frac{1}{3y - 1}\ :\left( - \frac{1}{y(3y - 1)} \right) =\]

\[= \frac{- y(3y - 1)}{(3y - 1)} = - y\]