ГДЗ по алгебре 8 класс Мерзляк Задание 239

\[\boxed{\text{239\ (239).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

Пояснение.

Решение.

\[1)\ 1 = 3^{0},\ 3 = 3^{1},\ 9 = 3^{2},\ \]

\[27 = 3^{3},\ 81 = 3^{4},\ \]

\[\frac{1}{3} = 3^{- 1},\frac{1}{9} = 3^{- 2},\frac{1}{27} = 3^{- 3},\]

\[\frac{1}{81} = 3^{- 4}\]

\[2)\ 1 = \left( \frac{1}{3} \right)^{0},\ 3 = \left( \frac{1}{3} \right)^{- 1},\ \]

\[9 = \left( \frac{1}{3} \right)^{- 2},\ 27 = \left( \frac{1}{3} \right)^{- 3},\ \]

\[81 = \left( \frac{1}{3} \right)^{- 4},\]

\[\frac{1}{3} = \left( \frac{1}{3} \right)^{1},\frac{1}{9} = \left( \frac{1}{3} \right)^{2},\frac{1}{27} =\]

\[= \left( \frac{1}{3} \right)^{3},\frac{1}{81} = \left( \frac{1}{3} \right)^{4}\]