\[\boxed{\mathbf{534\ (534).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\ \sqrt{48} - 6 - 4\sqrt{3} =\]
\[= 4\sqrt{3} - 6 - 4\sqrt{6} = - 6;\]
\[2)\ \sqrt{162} - 9\sqrt{2} + \sqrt{27} =\]
\[= 9\sqrt{2} - 9\sqrt{2} + 3\sqrt{3} = 3\sqrt{3}.\]