\[\boxed{\mathbf{539\ (539).\ }Еуроки\ - \ ДЗ\ без\ мороки}\]
\[1)\ \left( \sqrt{7} + 3 \right)\left( 3\sqrt{7} - 1 \right) =\]
\[= 3 \cdot 7 - \sqrt{7} + 9\sqrt{7} - 3 =\]
\[= 8\sqrt{7} + 18;\]
\[2)\ \left( 4\sqrt{2} - \sqrt{3} \right)\left( 2\sqrt{2} + 5\sqrt{3} \right) =\]
\[= 16 + 20\sqrt{6} - 2\sqrt{6} - 15 =\]
\[= 18\sqrt{6} + 1;\]
\[3)\ \left( \sqrt{p} - q \right)\sqrt{p} + q) = p - q^{2};\]
\[4)\ \left( 6 - \sqrt{13} \right)\left( 6 + \sqrt{13} \right) =\]
\[= 36 - 13 = 23;\]
\[5)\ \left( \sqrt{5} - x \right)\left( \sqrt{5} + x \right) = 5 - x^{2};\]
\[6)\ \left( \sqrt{19} + \sqrt{17} \right)\left( \sqrt{19} - \sqrt{17} \right) =\]
\[= 19 - 17 = 2;\]
\[7)\ \left( \sqrt{6} + \sqrt{2} \right)^{2} = 6 + 2\sqrt{12} + 2 =\]
\[= 4\sqrt{3} + 8;\]
\[8)\ \left( 3 - 2\sqrt{15} \right)² =\]
\[= 9 - 12\sqrt{15} + 60 =\]
\[= 69 - 12\sqrt{15}.\]